Given the partition {0,14,12,34,1}, find L(P) and U(P) for the integral ]∫102xdx.
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Problem:
Given the partition {0,14,12,34,1}, find L(P) and U(P) for the integral ]∫102xdx.
Answer:
L(P)=34 and U(P)=54
Given the partition {0,14,12,34,1}, find L(P) and U(P) for the integral ]∫102xdx.
L(P)=34 and U(P)=54