Prove that L(P)≤R(P)≤U(P).
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Problem:
Prove that L(P)≤R(P)≤U(P) where L(P) and U(P) are upper and lower sums, respectively, and R(P) is an arbitrary Riemann sum.
Answer:
It is true that L(P)≤R(P)≤U(P).
Prove that L(P)≤R(P)≤U(P) where L(P) and U(P) are upper and lower sums, respectively, and R(P) is an arbitrary Riemann sum.
It is true that L(P)≤R(P)≤U(P).