Chain Rule - Supporting Problem 3
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Problem:
Prove that if
- $g(x)$ is differentiable at $a$
- for all $\bar{\delta}\gt0$ there exists an $\bar{x}$ in the interval $(a-\bar{\delta},a)\cup(a,a+\delta)$ such that $g(x)=g(a)$
are true then $g'(a)=0$.
Answer:
$g'(a)=0$
